134040401323 has 2 divisors, whose sum is σ = 134040401324. Its totient is φ = 134040401322.

The previous prime is 134040401293. The next prime is 134040401329. The reversal of 134040401323 is 323104040431.

It is a strong prime.

It is an emirp because it is prime and its reverse (323104040431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134040401323 - 2⁵ = 134040401291 is a prime.

It is not a weakly prime, because it can be changed into another prime (134040401329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67020200661 + 67020200662.

It is an arithmetic number, because the mean of its divisors is an integer number (67020200662).

Almost surely, 2^134040401323 is an apocalyptic number.

134040401323 is a deficient number, since it is larger than the sum of its proper divisors (1).

134040401323 is an equidigital number, since it uses as much as digits as its factorization.

134040401323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 134040401323 its reverse (323104040431), we get a palindrome (457144441754).

The spelling of 134040401323 in words is "one hundred thirty-four billion, forty million, four hundred one thousand, three hundred twenty-three".