Base | Representation |
---|---|
bin | 11110011110100010111000… |
… | …110011111101001110100011 |
3 | 122120121010210201200220201012 |
4 | 132132202320303331032203 |
5 | 120032104310120021233 |
6 | 1153025154505331135 |
7 | 40143050026102463 |
oct | 3636427063751643 |
9 | 576533721626635 |
10 | 134040440001443 |
11 | 3978925aa54498 |
12 | 13049b28196aab |
13 | 59a3c6163bb51 |
14 | 25158402c3ba3 |
15 | 1076a759a1548 |
hex | 79e8b8cfd3a3 |
134040440001443 has 2 divisors, whose sum is σ = 134040440001444. Its totient is φ = 134040440001442.
The previous prime is 134040440001439. The next prime is 134040440001473. The reversal of 134040440001443 is 344100044040431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134040440001443 - 22 = 134040440001439 is a prime.
It is a super-3 number, since 3×1340404400014433 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (134040440001473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67020220000721 + 67020220000722.
It is an arithmetic number, because the mean of its divisors is an integer number (67020220000722).
Almost surely, 2134040440001443 is an apocalyptic number.
134040440001443 is a deficient number, since it is larger than the sum of its proper divisors (1).
134040440001443 is an equidigital number, since it uses as much as digits as its factorization.
134040440001443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36864, while the sum is 32.
Adding to 134040440001443 its reverse (344100044040431), we get a palindrome (478140484041874).
The spelling of 134040440001443 in words is "one hundred thirty-four trillion, forty billion, four hundred forty million, one thousand, four hundred forty-three".
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