Base | Representation |
---|---|
bin | 10011100000010111100… |
… | …001000010000000100100 |
3 | 11202010212110212020211201 |
4 | 103200113201002000210 |
5 | 133430142112100200 |
6 | 2503441001212244 |
7 | 165561651552565 |
oct | 23402741020044 |
9 | 4663773766751 |
10 | 1340424331300 |
11 | 47751a65465a |
12 | 197949491084 |
13 | 9952b059cc2 |
14 | 48c3c25216c |
15 | 24d02cc9c6a |
hex | 13817842024 |
1340424331300 has 36 divisors (see below), whose sum is σ = 2909883436096. Its totient is φ = 535955421600.
The previous prime is 1340424331297. The next prime is 1340424331339. The reversal of 1340424331300 is 31334240431.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2427336 + ... + 2927935.
Almost surely, 21340424331300 is an apocalyptic number.
1340424331300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1340424331300 is an abundant number, since it is smaller than the sum of its proper divisors (1569459104796).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1340424331300 is a wasteful number, since it uses less digits than its factorization.
1340424331300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5357788 (or 5357781 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 1340424331300 its reverse (31334240431), we get a palindrome (1371758571731).
The spelling of 1340424331300 in words is "one trillion, three hundred forty billion, four hundred twenty-four million, three hundred thirty-one thousand, three hundred".
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