1340431112399 has 2 divisors, whose sum is σ = 1340431112400. Its totient is φ = 1340431112398.

The previous prime is 1340431112341. The next prime is 1340431112407. The reversal of 1340431112399 is 9932111340431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340431112399 is a prime.

It is a super-4 number, since 4×1340431112399⁴ (a number of 50 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340431111399) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670215556199 + 670215556200.

It is an arithmetic number, because the mean of its divisors is an integer number (670215556200).

Almost surely, 2^{1340431112399} is an apocalyptic number.

1340431112399 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340431112399 is an equidigital number, since it uses as much as digits as its factorization.

1340431112399 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 1340431112399 in words is "one trillion, three hundred forty billion, four hundred thirty-one million, one hundred twelve thousand, three hundred ninety-nine".