13404313132 has 48 divisors (see below), whose sum is σ = 27282528000. Its totient is φ = 5643296064.

The previous prime is 13404313123. The next prime is 13404313133. The reversal of 13404313132 is 23131340431.

It is a super-2 number, since 2×13404313132² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13404313097 and 13404313106.

It is not an unprimeable number, because it can be changed into a prime (13404313133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3862294 + ... + 3865762.

It is an arithmetic number, because the mean of its divisors is an integer number (568386000).

Almost surely, 2^13404313132 is an apocalyptic number.

It is an amenable number.

13404313132 is an abundant number, since it is smaller than the sum of its proper divisors (13878214868).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13404313132 is a wasteful number, since it uses less digits than its factorization.

13404313132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5878 (or 5876 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13404313132 its reverse (23131340431), we get a palindrome (36535653563).

The spelling of 13404313132 in words is "thirteen billion, four hundred four million, three hundred thirteen thousand, one hundred thirty-two".