13404331211232 has 192 divisors, whose sum is σ = 39552483188736. Its totient is φ = 3943895408640.

The previous prime is 13404331211221. The next prime is 13404331211251. The reversal of 13404331211232 is 23211213340431.

It is a zygodrome in base 2.

It is a self number, because there is not a number n which added to its sum of digits gives 13404331211232.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 97266408 + ... + 97404120.

It is an arithmetic number, because the mean of its divisors is an integer number (206002516608).

Almost surely, 2^{13404331211232} is an apocalyptic number.

13404331211232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13404331211232, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19776241594368).

13404331211232 is an abundant number, since it is smaller than the sum of its proper divisors (26148151977504).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13404331211232 is a wasteful number, since it uses less digits than its factorization.

13404331211232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 141153 (or 141145 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 13404331211232 its reverse (23211213340431), we get a palindrome (36615544551663).

The spelling of 13404331211232 in words is "thirteen trillion, four hundred four billion, three hundred thirty-one million, two hundred eleven thousand, two hundred thirty-two".