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134043312112337 is a prime number
BaseRepresentation
bin11110011110100101100100…
…000000001100001011010001
3122120121102012220002021011202
4132132211210000030023101
5120032131200400043322
61153030351504520545
740143211142455565
oct3636454400141321
9576542186067152
10134043312112337
113978a4a4204961
121304a5aa020155
1359a42cb696654
142515a339196a5
151076b92bd2292
hex79e96400c2d1

134043312112337 has 2 divisors, whose sum is σ = 134043312112338. Its totient is φ = 134043312112336.

The previous prime is 134043312112301. The next prime is 134043312112399. The reversal of 134043312112337 is 733211213340431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 67526303718721 + 66517008393616 = 8217439^2 + 8155796^2 .

It is a cyclic number.

It is not a de Polignac number, because 134043312112337 - 218 = 134043311850193 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134043312112337.

It is not a weakly prime, because it can be changed into another prime (134043312112037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67021656056168 + 67021656056169.

It is an arithmetic number, because the mean of its divisors is an integer number (67021656056169).

Almost surely, 2134043312112337 is an apocalyptic number.

It is an amenable number.

134043312112337 is a deficient number, since it is larger than the sum of its proper divisors (1).

134043312112337 is an equidigital number, since it uses as much as digits as its factorization.

134043312112337 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108864, while the sum is 38.

Adding to 134043312112337 its reverse (733211213340431), we get a palindrome (867254525452768).

The spelling of 134043312112337 in words is "one hundred thirty-four trillion, forty-three billion, three hundred twelve million, one hundred twelve thousand, three hundred thirty-seven".