13404343211197 has 2 divisors, whose sum is σ = 13404343211198. Its totient is φ = 13404343211196.

The previous prime is 13404343211177. The next prime is 13404343211239. The reversal of 13404343211197 is 79111234340431.

13404343211197 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9204737312761 + 4199605898436 = 3033931^2 + 2049294^2 .

It is a cyclic number.

It is not a de Polignac number, because 13404343211197 - 2¹¹ = 13404343209149 is a prime.

It is a super-3 number, since 3×13404343211197³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13404343211177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702171605598 + 6702171605599.

It is an arithmetic number, because the mean of its divisors is an integer number (6702171605599).

Almost surely, 2^{13404343211197} is an apocalyptic number.

It is an amenable number.

13404343211197 is a deficient number, since it is larger than the sum of its proper divisors (1).

13404343211197 is an equidigital number, since it uses as much as digits as its factorization.

13404343211197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 217728, while the sum is 43.

The spelling of 13404343211197 in words is "thirteen trillion, four hundred four billion, three hundred forty-three million, two hundred eleven thousand, one hundred ninety-seven".