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13404343211204 = 2211304644163891
BaseRepresentation
bin1100001100001111000100…
…0111011001010011000100
31202110102221201120212222112
43003003301013121103010
53224104043330224304
644301511550520152
72552301056236631
oct303036107312304
952412851525875
1013404343211204
1142a8828323a40
121605a27506058
137630410652ca
14344ab8d5d188
15183a274ecb6e
hexc30f11d94c4

13404343211204 has 12 divisors (see below), whose sum is σ = 25590109766928. Its totient is φ = 6092883277800.

The previous prime is 13404343211197. The next prime is 13404343211239. The reversal of 13404343211204 is 40211234340431.

It is a super-3 number, since 3×134043432112043 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152322081902 + ... + 152322081989.

It is an arithmetic number, because the mean of its divisors is an integer number (2132509147244).

Almost surely, 213404343211204 is an apocalyptic number.

It is an amenable number.

13404343211204 is a deficient number, since it is larger than the sum of its proper divisors (12185766555724).

13404343211204 is a wasteful number, since it uses less digits than its factorization.

13404343211204 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 304644163906 (or 304644163904 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13404343211204 its reverse (40211234340431), we get a palindrome (53615577551635).

The spelling of 13404343211204 in words is "thirteen trillion, four hundred four billion, three hundred forty-three million, two hundred eleven thousand, two hundred four".

Divisors: 1 2 4 11 22 44 304644163891 609288327782 1218576655564 3351085802801 6702171605602 13404343211204