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13404436148149 is a prime number
BaseRepresentation
bin1100001100001111011010…
…1001111010111110110101
31202110110012012110120111121
43003003312221322332311
53224104241123220044
644301525110503541
72552303265214054
oct303036651727665
952413165416447
1013404436148149
1142a8875830932
121605a52664bb1
137630573a4c97
14344ac743239b
15183a30759984
hexc30f6a7afb5

13404436148149 has 2 divisors, whose sum is σ = 13404436148150. Its totient is φ = 13404436148148.

The previous prime is 13404436148143. The next prime is 13404436148161. The reversal of 13404436148149 is 94184163440431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10755087455025 + 2649348693124 = 3279495^2 + 1627682^2 .

It is a cyclic number.

It is not a de Polignac number, because 13404436148149 - 219 = 13404435623861 is a prime.

It is a super-2 number, since 2×134044361481492 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13404436148096 and 13404436148105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13404436148143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702218074074 + 6702218074075.

It is an arithmetic number, because the mean of its divisors is an integer number (6702218074075).

Almost surely, 213404436148149 is an apocalyptic number.

It is an amenable number.

13404436148149 is a deficient number, since it is larger than the sum of its proper divisors (1).

13404436148149 is an equidigital number, since it uses as much as digits as its factorization.

13404436148149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3981312, while the sum is 52.

The spelling of 13404436148149 in words is "thirteen trillion, four hundred four billion, four hundred thirty-six million, one hundred forty-eight thousand, one hundred forty-nine".