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1340444029973 is a prime number
BaseRepresentation
bin10011100000011000101…
…100001011010000010101
311202010220211221001100012
4103200120230023100111
5133430212132424343
62503442543330005
7165562311155246
oct23403054132025
94663824831305
101340444029973
1147752a789554
12197953bb0905
1399532166219
1448c40adcccd
1524d048bb718
hex13818b0b415

1340444029973 has 2 divisors, whose sum is σ = 1340444029974. Its totient is φ = 1340444029972.

The previous prime is 1340444029913. The next prime is 1340444029997. The reversal of 1340444029973 is 3799204440431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1067382392164 + 273061637809 = 1033142^2 + 522553^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340444029973 - 216 = 1340443964437 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340444029913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670222014986 + 670222014987.

It is an arithmetic number, because the mean of its divisors is an integer number (670222014987).

Almost surely, 21340444029973 is an apocalyptic number.

It is an amenable number.

1340444029973 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340444029973 is an equidigital number, since it uses as much as digits as its factorization.

1340444029973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2612736, while the sum is 50.

The spelling of 1340444029973 in words is "one trillion, three hundred forty billion, four hundred forty-four million, twenty-nine thousand, nine hundred seventy-three".