1340444777081 has 2 divisors, whose sum is σ = 1340444777082. Its totient is φ = 1340444777080.

The previous prime is 1340444777057. The next prime is 1340444777083. The reversal of 1340444777081 is 1807774440431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1114891021456 + 225553755625 = 1055884^2 + 474925^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340444777081 - 2³⁰ = 1339371035257 is a prime.

It is a super-2 number, since 2×1340444777081² (a number of 25 digits) contains 22 as substring.

Together with 1340444777083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1340444777083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670222388540 + 670222388541.

It is an arithmetic number, because the mean of its divisors is an integer number (670222388541).

Almost surely, 2^{1340444777081} is an apocalyptic number.

It is an amenable number.

1340444777081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340444777081 is an equidigital number, since it uses as much as digits as its factorization.

1340444777081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2107392, while the sum is 50.

The spelling of 1340444777081 in words is "one trillion, three hundred forty billion, four hundred forty-four million, seven hundred seventy-seven thousand, eighty-one".