Base | Representation |
---|---|
bin | 10011100000011010011… |
… | …100001111000010101101 |
3 | 11202010222220012111010212 |
4 | 103200122130033002231 |
5 | 133430242142434423 |
6 | 2503445513112205 |
7 | 165563115643436 |
oct | 23403234170255 |
9 | 4663886174125 |
10 | 1340473405613 |
11 | 477545322941 |
12 | 1979619b8665 |
13 | 9953827cc64 |
14 | 48c4498848d |
15 | 24d07270578 |
hex | 1381a70f0ad |
1340473405613 has 2 divisors, whose sum is σ = 1340473405614. Its totient is φ = 1340473405612.
The previous prime is 1340473405589. The next prime is 1340473405657. The reversal of 1340473405613 is 3165043740431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1258125642244 + 82347763369 = 1121662^2 + 286963^2 .
It is a cyclic number.
It is not a de Polignac number, because 1340473405613 - 28 = 1340473405357 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340473455613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670236702806 + 670236702807.
It is an arithmetic number, because the mean of its divisors is an integer number (670236702807).
Almost surely, 21340473405613 is an apocalyptic number.
It is an amenable number.
1340473405613 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340473405613 is an equidigital number, since it uses as much as digits as its factorization.
1340473405613 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 41.
The spelling of 1340473405613 in words is "one trillion, three hundred forty billion, four hundred seventy-three million, four hundred five thousand, six hundred thirteen".
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