Base | Representation |
---|---|
bin | 10011100000011010011… |
… | …111111011100000001111 |
3 | 11202010222222000200201221 |
4 | 103200122133323200033 |
5 | 133430242414433114 |
6 | 2503445545544211 |
7 | 165563130116254 |
oct | 23403237734017 |
9 | 4663888020657 |
10 | 1340474374159 |
11 | 477545924598 |
12 | 1979621a5067 |
13 | 9953852ba6b |
14 | 48c44b5b42b |
15 | 24d073b2524 |
hex | 1381a7fb80f |
1340474374159 has 2 divisors, whose sum is σ = 1340474374160. Its totient is φ = 1340474374158.
The previous prime is 1340474374097. The next prime is 1340474374177. The reversal of 1340474374159 is 9514734740431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1340474374159 - 29 = 1340474373647 is a prime.
It is a super-3 number, since 3×13404743741593 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340474374559) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670237187079 + 670237187080.
It is an arithmetic number, because the mean of its divisors is an integer number (670237187080).
Almost surely, 21340474374159 is an apocalyptic number.
1340474374159 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340474374159 is an equidigital number, since it uses as much as digits as its factorization.
1340474374159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5080320, while the sum is 52.
The spelling of 1340474374159 in words is "one trillion, three hundred forty billion, four hundred seventy-four million, three hundred seventy-four thousand, one hundred fifty-nine".
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