134053225434311 has 2 divisors, whose sum is σ = 134053225434312. Its totient is φ = 134053225434310.

The previous prime is 134053225434307. The next prime is 134053225434341. The reversal of 134053225434311 is 113434522350431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 134053225434311 - 2² = 134053225434307 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134053225434341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67026612717155 + 67026612717156.

It is an arithmetic number, because the mean of its divisors is an integer number (67026612717156).

Almost surely, 2^{134053225434311} is an apocalyptic number.

134053225434311 is a deficient number, since it is larger than the sum of its proper divisors (1).

134053225434311 is an equidigital number, since it uses as much as digits as its factorization.

134053225434311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 134053225434311 its reverse (113434522350431), we get a palindrome (247487747784742).

The spelling of 134053225434311 in words is "one hundred thirty-four trillion, fifty-three billion, two hundred twenty-five million, four hundred thirty-four thousand, three hundred eleven".