Base | Representation |
---|---|
bin | 10011100000011110100… |
… | …010110000100001101011 |
3 | 11202011011200200211220012 |
4 | 103200132202300201223 |
5 | 133430412302140431 |
6 | 2503500412122135 |
7 | 165564612620531 |
oct | 23403642604153 |
9 | 4664150624805 |
10 | 1340542224491 |
11 | 477580157548 |
12 | 197980a6634b |
13 | 995495c6ca2 |
14 | 48c4db80151 |
15 | 24d0d31622b |
hex | 1381e8b086b |
1340542224491 has 2 divisors, whose sum is σ = 1340542224492. Its totient is φ = 1340542224490.
The previous prime is 1340542224487. The next prime is 1340542224529. The reversal of 1340542224491 is 1944222450431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1340542224491 - 22 = 1340542224487 is a prime.
It is not a weakly prime, because it can be changed into another prime (1340542224421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670271112245 + 670271112246.
It is an arithmetic number, because the mean of its divisors is an integer number (670271112246).
Almost surely, 21340542224491 is an apocalyptic number.
1340542224491 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340542224491 is an equidigital number, since it uses as much as digits as its factorization.
1340542224491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 276480, while the sum is 41.
It can be divided in two parts, 13 and 40542224491, that added together give a palindrome (40542224504).
The spelling of 1340542224491 in words is "one trillion, three hundred forty billion, five hundred forty-two million, two hundred twenty-four thousand, four hundred ninety-one".
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