Base | Representation |
---|---|
bin | 1100001100010011000101… |
… | …1011100101010001111011 |
3 | 1202110112201220222111001201 |
4 | 3003010301123211101323 |
5 | 3224113301043314422 |
6 | 44302211014155031 |
7 | 2552336601001003 |
oct | 303046133452173 |
9 | 52415656874051 |
10 | 13405422244987 |
11 | 42a9231418aa3 |
12 | 1606088952a77 |
13 | 763183784b36 |
14 | 344b7c3a1003 |
15 | 183a8c0e1727 |
hex | c31316e547b |
13405422244987 has 2 divisors, whose sum is σ = 13405422244988. Its totient is φ = 13405422244986.
The previous prime is 13405422244969. The next prime is 13405422244999. The reversal of 13405422244987 is 78944222450431.
13405422244987 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13405422244987 - 231 = 13403274761339 is a prime.
It is not a weakly prime, because it can be changed into another prime (13405422244927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702711122493 + 6702711122494.
It is an arithmetic number, because the mean of its divisors is an integer number (6702711122494).
Almost surely, 213405422244987 is an apocalyptic number.
13405422244987 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405422244987 is an equidigital number, since it uses as much as digits as its factorization.
13405422244987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15482880, while the sum is 55.
The spelling of 13405422244987 in words is "thirteen trillion, four hundred five billion, four hundred twenty-two million, two hundred forty-four thousand, nine hundred eighty-seven".
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