Base | Representation |
---|---|
bin | 1100001100010011000101… |
… | …1011100101010010000111 |
3 | 1202110112201220222111002011 |
4 | 3003010301123211102013 |
5 | 3224113301043314444 |
6 | 44302211014155051 |
7 | 2552336601001021 |
oct | 303046133452207 |
9 | 52415656874064 |
10 | 13405422244999 |
11 | 42a9231419004 |
12 | 1606088952a87 |
13 | 763183784b45 |
14 | 344b7c3a1011 |
15 | 183a8c0e1734 |
hex | c31316e5487 |
13405422244999 has 2 divisors, whose sum is σ = 13405422245000. Its totient is φ = 13405422244998.
The previous prime is 13405422244987. The next prime is 13405422245023. The reversal of 13405422244999 is 99944222450431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13405422244999 - 25 = 13405422244967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13405422244939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702711122499 + 6702711122500.
It is an arithmetic number, because the mean of its divisors is an integer number (6702711122500).
Almost surely, 213405422244999 is an apocalyptic number.
13405422244999 is a deficient number, since it is larger than the sum of its proper divisors (1).
13405422244999 is an equidigital number, since it uses as much as digits as its factorization.
13405422244999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22394880, while the sum is 58.
The spelling of 13405422244999 in words is "thirteen trillion, four hundred five billion, four hundred twenty-two million, two hundred forty-four thousand, nine hundred ninety-nine".
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