13405424212111 has 2 divisors, whose sum is σ = 13405424212112. Its totient is φ = 13405424212110.

The previous prime is 13405424212099. The next prime is 13405424212127. The reversal of 13405424212111 is 11121242450431.

It is a weak prime.

It is an emirp because it is prime and its reverse (11121242450431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13405424212111 - 2⁷ = 13405424211983 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13405424212711) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702712106055 + 6702712106056.

It is an arithmetic number, because the mean of its divisors is an integer number (6702712106056).

Almost surely, 2^{13405424212111} is an apocalyptic number.

13405424212111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405424212111 is an equidigital number, since it uses as much as digits as its factorization.

13405424212111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 13405424212111 its reverse (11121242450431), we get a palindrome (24526666662542).

The spelling of 13405424212111 in words is "thirteen trillion, four hundred five billion, four hundred twenty-four million, two hundred twelve thousand, one hundred eleven".