Base | Representation |
---|---|
bin | 1100001100010011000111… |
… | …1011001111011011101111 |
3 | 1202110112202111121010022200 |
4 | 3003010301323033123233 |
5 | 3224113310204402421 |
6 | 44302211512112543 |
7 | 2552340031354464 |
oct | 303046173173357 |
9 | 52415674533280 |
10 | 13405430544111 |
11 | 42a9236077281 |
12 | 160608b695753 |
13 | 7631853cc468 |
14 | 344b7d52166b |
15 | 183a8cbd0726 |
hex | c3131ecf6ef |
13405430544111 has 24 divisors (see below), whose sum is σ = 20060431494480. Its totient is φ = 8616149114496.
The previous prime is 13405430544029. The next prime is 13405430544127. The reversal of 13405430544111 is 11144503450431.
13405430544111 is a `hidden beast` number, since 1 + 34 + 0 + 54 + 30 + 544 + 1 + 1 + 1 = 666.
It is not a de Polignac number, because 13405430544111 - 27 = 13405430543983 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13405430544161) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 37421886 + ... + 37778411.
It is an arithmetic number, because the mean of its divisors is an integer number (835851312270).
Almost surely, 213405430544111 is an apocalyptic number.
13405430544111 is a deficient number, since it is larger than the sum of its proper divisors (6655000950369).
13405430544111 is a wasteful number, since it uses less digits than its factorization.
13405430544111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75201015 (or 75201012 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 36.
Adding to 13405430544111 its reverse (11144503450431), we get a palindrome (24549933994542).
The spelling of 13405430544111 in words is "thirteen trillion, four hundred five billion, four hundred thirty million, five hundred forty-four thousand, one hundred eleven".
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