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13405433304247 is a prime number
BaseRepresentation
bin1100001100010011001000…
…0101110001010010110111
31202110112202200210100111221
43003010302011301102313
53224113311411213442
644302212051211211
72552340064001515
oct303046205612267
952415680710457
1013405433304247
1142a9237691a86
1216060905a6b07
13763185b5788a
14344b7da3d4b5
15183a8d078467
hexc31321714b7

13405433304247 has 2 divisors, whose sum is σ = 13405433304248. Its totient is φ = 13405433304246.

The previous prime is 13405433304191. The next prime is 13405433304283. The reversal of 13405433304247 is 74240333450431.

It is a strong prime.

It is an emirp because it is prime and its reverse (74240333450431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13405433304247 - 215 = 13405433271479 is a prime.

It is a super-2 number, since 2×134054333042472 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13405433307247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702716652123 + 6702716652124.

It is an arithmetic number, because the mean of its divisors is an integer number (6702716652124).

Almost surely, 213405433304247 is an apocalyptic number.

13405433304247 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405433304247 is an equidigital number, since it uses as much as digits as its factorization.

13405433304247 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 43.

Adding to 13405433304247 its reverse (74240333450431), we get a palindrome (87645766754678).

The spelling of 13405433304247 in words is "thirteen trillion, four hundred five billion, four hundred thirty-three million, three hundred four thousand, two hundred forty-seven".