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13405504213202 = 26702752106601
BaseRepresentation
bin1100001100010011011001…
…0100010001000011010010
31202110112221122012220022112
43003010312110101003102
53224113433034310302
644302223103105322
72552341614502253
oct303046624210322
952415848186275
1013405504213202
1142a9273713a22
1216060b02a2242
1376319775403a
14344b8921ab2a
15183a943d3552
hexc31365110d2

13405504213202 has 4 divisors (see below), whose sum is σ = 20108256319806. Its totient is φ = 6702752106600.

The previous prime is 13405504213181. The next prime is 13405504213301. The reversal of 13405504213202 is 20231240550431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10328388315961 + 3077115897241 = 3213781^2 + 1754171^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3351376053299 + ... + 3351376053302.

Almost surely, 213405504213202 is an apocalyptic number.

13405504213202 is a deficient number, since it is larger than the sum of its proper divisors (6702752106604).

13405504213202 is an equidigital number, since it uses as much as digits as its factorization.

13405504213202 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6702752106603.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 13405504213202 its reverse (20231240550431), we get a palindrome (33636744763633).

The spelling of 13405504213202 in words is "thirteen trillion, four hundred five billion, five hundred four million, two hundred thirteen thousand, two hundred two".

Divisors: 1 2 6702752106601 13405504213202