Base | Representation |
---|---|
bin | 1100001100010011011001… |
… | …0100010001000011010010 |
3 | 1202110112221122012220022112 |
4 | 3003010312110101003102 |
5 | 3224113433034310302 |
6 | 44302223103105322 |
7 | 2552341614502253 |
oct | 303046624210322 |
9 | 52415848186275 |
10 | 13405504213202 |
11 | 42a9273713a22 |
12 | 16060b02a2242 |
13 | 76319775403a |
14 | 344b8921ab2a |
15 | 183a943d3552 |
hex | c31365110d2 |
13405504213202 has 4 divisors (see below), whose sum is σ = 20108256319806. Its totient is φ = 6702752106600.
The previous prime is 13405504213181. The next prime is 13405504213301. The reversal of 13405504213202 is 20231240550431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10328388315961 + 3077115897241 = 3213781^2 + 1754171^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3351376053299 + ... + 3351376053302.
Almost surely, 213405504213202 is an apocalyptic number.
13405504213202 is a deficient number, since it is larger than the sum of its proper divisors (6702752106604).
13405504213202 is an equidigital number, since it uses as much as digits as its factorization.
13405504213202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6702752106603.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 13405504213202 its reverse (20231240550431), we get a palindrome (33636744763633).
The spelling of 13405504213202 in words is "thirteen trillion, four hundred five billion, five hundred four million, two hundred thirteen thousand, two hundred two".
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