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20231240550431 is a prime number
BaseRepresentation
bin1001001100110011100111…
…11010000000100000011111
32122122002100221100120210112
410212121303322000200133
510122432040040103211
6111010034213400235
74155442000202561
oct446316372004037
978562327316715
1020231240550431
1164a0025955159
122328b4963907b
13b39a4a9b96c1
144dd2a9431331
152513dacce88b
hex126673e8081f

20231240550431 has 2 divisors, whose sum is σ = 20231240550432. Its totient is φ = 20231240550430.

The previous prime is 20231240550379. The next prime is 20231240550461. The reversal of 20231240550431 is 13405504213202.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20231240550431 is a prime.

It is a super-2 number, since 2×202312405504312 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20231240550461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10115620275215 + 10115620275216.

It is an arithmetic number, because the mean of its divisors is an integer number (10115620275216).

Almost surely, 220231240550431 is an apocalyptic number.

20231240550431 is a deficient number, since it is larger than the sum of its proper divisors (1).

20231240550431 is an equidigital number, since it uses as much as digits as its factorization.

20231240550431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 32.

Adding to 20231240550431 its reverse (13405504213202), we get a palindrome (33636744763633).

The spelling of 20231240550431 in words is "twenty trillion, two hundred thirty-one billion, two hundred forty million, five hundred fifty thousand, four hundred thirty-one".