Base | Representation |
---|---|
bin | 1100001100010011011001… |
… | …0100101101111010011111 |
3 | 1202110112221122102220111002 |
4 | 3003010312110231322133 |
5 | 3224113433102101143 |
6 | 44302223105420515 |
7 | 2552341615504031 |
oct | 303046624557237 |
9 | 52415848386432 |
10 | 13405504331423 |
11 | 42a9273794826 |
12 | 16060b033a73b |
13 | 763197795aa9 |
14 | 344b8924bc51 |
15 | 183a944085b8 |
hex | c313652de9f |
13405504331423 has 8 divisors (see below), whose sum is σ = 14302415041200. Its totient is φ = 12520632691840.
The previous prime is 13405504331419. The next prime is 13405504331437. The reversal of 13405504331423 is 32413340550431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13405504331423 - 22 = 13405504331419 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13405504331413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3009765248 + ... + 3009769701.
It is an arithmetic number, because the mean of its divisors is an integer number (1787801880150).
Almost surely, 213405504331423 is an apocalyptic number.
13405504331423 is a deficient number, since it is larger than the sum of its proper divisors (896910709777).
13405504331423 is a wasteful number, since it uses less digits than its factorization.
13405504331423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6019535097.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 13405504331423 its reverse (32413340550431), we get a palindrome (45818844881854).
The spelling of 13405504331423 in words is "thirteen trillion, four hundred five billion, five hundred four million, three hundred thirty-one thousand, four hundred twenty-three".
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