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1340551103 is a prime number
BaseRepresentation
bin100111111100111…
…0010111110111111
310110102111001101212
41033321302332333
510221140113403
6341004355035
745135332153
oct11771627677
93412431355
101340551103
11628784981
12314b45a7b
13184965608
14ca079063
157ca504d8
hex4fe72fbf

1340551103 has 2 divisors, whose sum is σ = 1340551104. Its totient is φ = 1340551102.

The previous prime is 1340551081. The next prime is 1340551117. The reversal of 1340551103 is 3011550431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340551103 - 216 = 1340485567 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340551193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670275551 + 670275552.

It is an arithmetic number, because the mean of its divisors is an integer number (670275552).

Almost surely, 21340551103 is an apocalyptic number.

1340551103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340551103 is an equidigital number, since it uses as much as digits as its factorization.

1340551103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 23.

The square root of 1340551103 is about 36613.5371549923. The cubic root of 1340551103 is about 1102.6248891933.

The spelling of 1340551103 in words is "one billion, three hundred forty million, five hundred fifty-one thousand, one hundred three".