13405541345531 has 2 divisors, whose sum is σ = 13405541345532. Its totient is φ = 13405541345530.

The previous prime is 13405541345453. The next prime is 13405541345533. The reversal of 13405541345531 is 13554314550431.

13405541345531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13405541345531 - 2³⁸ = 13130663438587 is a prime.

It is a super-2 number, since 2×13405541345531² (a number of 27 digits) contains 22 as substring.

Together with 13405541345533, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13405541345533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6702770672765 + 6702770672766.

It is an arithmetic number, because the mean of its divisors is an integer number (6702770672766).

Almost surely, 2^{13405541345531} is an apocalyptic number.

13405541345531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13405541345531 is an equidigital number, since it uses as much as digits as its factorization.

13405541345531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080000, while the sum is 44.

Adding to 13405541345531 its reverse (13554314550431), we get a palindrome (26959855895962).

The spelling of 13405541345531 in words is "thirteen trillion, four hundred five billion, five hundred forty-one million, three hundred forty-five thousand, five hundred thirty-one".