Base | Representation |
---|---|
bin | 10011100000011111010… |
… | …000001110110101111111 |
3 | 11202011012112010110222010 |
4 | 103200133100032311333 |
5 | 133430423330121101 |
6 | 2503501515422303 |
7 | 165565116136614 |
oct | 23403720166577 |
9 | 4664175113863 |
10 | 1340554145151 |
11 | 477586959731 |
12 | 197984a54993 |
13 | 9954bc0bb30 |
14 | 48c515a450b |
15 | 24d0e3bd2d6 |
hex | 1381f40ed7f |
1340554145151 has 16 divisors (see below), whose sum is σ = 1924920346496. Its totient is φ = 824946931296.
The previous prime is 1340554145101. The next prime is 1340554145167. The reversal of 1340554145151 is 1515414550431.
It is not a de Polignac number, because 1340554145151 - 213 = 1340554136959 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340554145101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4937916 + ... + 5202318.
It is an arithmetic number, because the mean of its divisors is an integer number (120307521656).
Almost surely, 21340554145151 is an apocalyptic number.
1340554145151 is a deficient number, since it is larger than the sum of its proper divisors (584366201345).
1340554145151 is a wasteful number, since it uses less digits than its factorization.
1340554145151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 394422.
The product of its (nonzero) digits is 120000, while the sum is 39.
Adding to 1340554145151 its reverse (1515414550431), we get a palindrome (2855968695582).
The spelling of 1340554145151 in words is "one trillion, three hundred forty billion, five hundred fifty-four million, one hundred forty-five thousand, one hundred fifty-one".
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