Base | Representation |
---|---|
bin | 10011100000011111010… |
… | …000001110110110001111 |
3 | 11202011012112010110222201 |
4 | 103200133100032312033 |
5 | 133430423330121132 |
6 | 2503501515422331 |
7 | 165565116136636 |
oct | 23403720166617 |
9 | 4664175113881 |
10 | 1340554145167 |
11 | 477586959746 |
12 | 197984a549a7 |
13 | 9954bc0bb43 |
14 | 48c515a451d |
15 | 24d0e3bd2e7 |
hex | 1381f40ed8f |
1340554145167 has 2 divisors, whose sum is σ = 1340554145168. Its totient is φ = 1340554145166.
The previous prime is 1340554145101. The next prime is 1340554145221. The reversal of 1340554145167 is 7615414550431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1340554145167 is a prime.
It is a super-2 number, since 2×13405541451672 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340554145867) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670277072583 + 670277072584.
It is an arithmetic number, because the mean of its divisors is an integer number (670277072584).
Almost surely, 21340554145167 is an apocalyptic number.
1340554145167 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340554145167 is an equidigital number, since it uses as much as digits as its factorization.
1340554145167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008000, while the sum is 46.
Adding to 1340554145167 its reverse (7615414550431), we get a palindrome (8955968695598).
The spelling of 1340554145167 in words is "one trillion, three hundred forty billion, five hundred fifty-four million, one hundred forty-five thousand, one hundred sixty-seven".
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