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1340554145101 is a prime number
BaseRepresentation
bin10011100000011111010…
…000001110110101001101
311202011012112010110220021
4103200133100032311031
5133430423330120401
62503501515422141
7165565116136513
oct23403720166515
94664175113807
101340554145101
11477586959696
12197984a54951
139954bc0bac2
1448c515a44b3
1524d0e3bd2a1
hex1381f40ed4d

1340554145101 has 2 divisors, whose sum is σ = 1340554145102. Its totient is φ = 1340554145100.

The previous prime is 1340554145059. The next prime is 1340554145167. The reversal of 1340554145101 is 1015414550431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 944725680900 + 395828464201 = 971970^2 + 629149^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340554145101 - 223 = 1340545756493 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340554142101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670277072550 + 670277072551.

It is an arithmetic number, because the mean of its divisors is an integer number (670277072551).

Almost surely, 21340554145101 is an apocalyptic number.

It is an amenable number.

1340554145101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340554145101 is an equidigital number, since it uses as much as digits as its factorization.

1340554145101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24000, while the sum is 34.

Adding to 1340554145101 its reverse (1015414550431), we get a palindrome (2355968695532).

The spelling of 1340554145101 in words is "one trillion, three hundred forty billion, five hundred fifty-four million, one hundred forty-five thousand, one hundred one".