Base | Representation |
---|---|
bin | 10011100000100010110… |
… | …001000111010010000101 |
3 | 11202011100122001112010102 |
4 | 103200202301013102011 |
5 | 133431033423042311 |
6 | 2503511423133445 |
7 | 165566433205643 |
oct | 23404261072205 |
9 | 4664318045112 |
10 | 1340613096581 |
11 | 477607163820 |
12 | 1979a0744285 |
13 | 9955b1ac735 |
14 | 48c5934c193 |
15 | 24d1466543b |
hex | 13822c47485 |
1340613096581 has 16 divisors (see below), whose sum is σ = 1477836628800. Its totient is φ = 1205952468480.
The previous prime is 1340613096539. The next prime is 1340613096583. The reversal of 1340613096581 is 1856903160431.
It is a cyclic number.
It is not a de Polignac number, because 1340613096581 - 214 = 1340613080197 is a prime.
It is a super-2 number, since 2×13406130965812 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340613096583) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5816270 + ... + 6042368.
It is an arithmetic number, because the mean of its divisors is an integer number (92364789300).
Almost surely, 21340613096581 is an apocalyptic number.
1340613096581 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1340613096581 is a deficient number, since it is larger than the sum of its proper divisors (137223532219).
1340613096581 is a wasteful number, since it uses less digits than its factorization.
1340613096581 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 231764.
The product of its (nonzero) digits is 466560, while the sum is 47.
The spelling of 1340613096581 in words is "one trillion, three hundred forty billion, six hundred thirteen million, ninety-six thousand, five hundred eighty-one".
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