Base | Representation |
---|---|
bin | 1100001100010101110011… |
… | …1000110110101111110111 |
3 | 1202110121121201220022000122 |
4 | 3003011130320312233313 |
5 | 3224121244220321444 |
6 | 44302411221202155 |
7 | 2552363633125346 |
oct | 303053470665767 |
9 | 52417551808018 |
10 | 13406151338999 |
11 | 42a9575a2a131 |
12 | 1606250b6035b |
13 | 76326b83ca03 |
14 | 344c0b14db5d |
15 | 183ad110e4ee |
hex | c315ce36bf7 |
13406151338999 has 2 divisors, whose sum is σ = 13406151339000. Its totient is φ = 13406151338998.
The previous prime is 13406151338959. The next prime is 13406151339023. The reversal of 13406151338999 is 99983315160431.
It is a strong prime.
It is an emirp because it is prime and its reverse (99983315160431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13406151338999 - 224 = 13406134561783 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13406151338959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6703075669499 + 6703075669500.
It is an arithmetic number, because the mean of its divisors is an integer number (6703075669500).
Almost surely, 213406151338999 is an apocalyptic number.
13406151338999 is a deficient number, since it is larger than the sum of its proper divisors (1).
13406151338999 is an equidigital number, since it uses as much as digits as its factorization.
13406151338999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18895680, while the sum is 62.
The spelling of 13406151338999 in words is "thirteen trillion, four hundred six billion, one hundred fifty-one million, three hundred thirty-eight thousand, nine hundred ninety-nine".
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