13406509601 has 2 divisors, whose sum is σ = 13406509602. Its totient is φ = 13406509600.

The previous prime is 13406509549. The next prime is 13406509603. The reversal of 13406509601 is 10690560431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11363560000 + 2042949601 = 106600^2 + 45199^2 .

It is a cyclic number.

It is not a de Polignac number, because 13406509601 - 2¹⁸ = 13406247457 is a prime.

Together with 13406509603, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13406509603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6703254800 + 6703254801.

It is an arithmetic number, because the mean of its divisors is an integer number (6703254801).

Almost surely, 2^13406509601 is an apocalyptic number.

It is an amenable number.

13406509601 is a deficient number, since it is larger than the sum of its proper divisors (1).

13406509601 is an equidigital number, since it uses as much as digits as its factorization.

13406509601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 35.

The spelling of 13406509601 in words is "thirteen billion, four hundred six million, five hundred nine thousand, six hundred one".