Base | Representation |
---|---|
bin | 111110011011100000… |
… | …1110101110000101111 |
3 | 110211001101010012021111 |
4 | 1330313001311300233 |
5 | 4144032201343112 |
6 | 141331205412451 |
7 | 12454211346136 |
oct | 1746701656057 |
9 | 424041105244 |
10 | 134067215407 |
11 | 519484a2284 |
12 | 21b96a0a127 |
13 | c8476cb478 |
14 | 66bb71891d |
15 | 3749e645a7 |
hex | 1f37075c2f |
134067215407 has 2 divisors, whose sum is σ = 134067215408. Its totient is φ = 134067215406.
The previous prime is 134067215363. The next prime is 134067215411. The reversal of 134067215407 is 704512760431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134067215407 - 211 = 134067213359 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 134067215407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134067215437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67033607703 + 67033607704.
It is an arithmetic number, because the mean of its divisors is an integer number (67033607704).
Almost surely, 2134067215407 is an apocalyptic number.
134067215407 is a deficient number, since it is larger than the sum of its proper divisors (1).
134067215407 is an equidigital number, since it uses as much as digits as its factorization.
134067215407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 141120, while the sum is 40.
Adding to 134067215407 its reverse (704512760431), we get a palindrome (838579975838).
The spelling of 134067215407 in words is "one hundred thirty-four billion, sixty-seven million, two hundred fifteen thousand, four hundred seven".
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