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13406773404097 is a prime number
BaseRepresentation
bin1100001100011000000111…
…1101110110000111000001
31202110200020002102110220201
43003012001331312013001
53224124032442412342
644302553042205201
72552415225444253
oct303060175660701
952420202373821
1013406773404097
1142a9865088917
1216063a5353801
1376333a692978
14344c699dbcd3
15183b1aa39db7
hexc3181f761c1

13406773404097 has 2 divisors, whose sum is σ = 13406773404098. Its totient is φ = 13406773404096.

The previous prime is 13406773404083. The next prime is 13406773404127. The reversal of 13406773404097 is 79040437760431.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7423314379776 + 5983459024321 = 2724576^2 + 2446111^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13406773404097 is a prime.

It is a super-2 number, since 2×134067734040972 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13406773404077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6703386702048 + 6703386702049.

It is an arithmetic number, because the mean of its divisors is an integer number (6703386702049).

Almost surely, 213406773404097 is an apocalyptic number.

It is an amenable number.

13406773404097 is a deficient number, since it is larger than the sum of its proper divisors (1).

13406773404097 is an equidigital number, since it uses as much as digits as its factorization.

13406773404097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10668672, while the sum is 55.

The spelling of 13406773404097 in words is "thirteen trillion, four hundred six billion, seven hundred seventy-three million, four hundred four thousand, ninety-seven".