Base | Representation |
---|---|
bin | 10011100000101000001… |
… | …010011101010111000101 |
3 | 11202011120221101221002112 |
4 | 103200220022131113011 |
5 | 133431230112023233 |
6 | 2503524415350405 |
7 | 165601612540064 |
oct | 23405012352705 |
9 | 4664527357075 |
10 | 1340703626693 |
11 | 4776532773a2 |
12 | 197a06b22405 |
13 | 99573b88a52 |
14 | 48c673961db |
15 | 24d1c599048 |
hex | 1382829d5c5 |
1340703626693 has 2 divisors, whose sum is σ = 1340703626694. Its totient is φ = 1340703626692.
The previous prime is 1340703626659. The next prime is 1340703626707. The reversal of 1340703626693 is 3966263070431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1254832357249 + 85871269444 = 1120193^2 + 293038^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1340703626693 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340703629693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670351813346 + 670351813347.
It is an arithmetic number, because the mean of its divisors is an integer number (670351813347).
Almost surely, 21340703626693 is an apocalyptic number.
It is an amenable number.
1340703626693 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340703626693 is an equidigital number, since it uses as much as digits as its factorization.
1340703626693 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2939328, while the sum is 50.
The spelling of 1340703626693 in words is "one trillion, three hundred forty billion, seven hundred three million, six hundred twenty-six thousand, six hundred ninety-three".
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