13408080666731 has 2 divisors, whose sum is σ = 13408080666732. Its totient is φ = 13408080666730.

The previous prime is 13408080666719. The next prime is 13408080666787. The reversal of 13408080666731 is 13766608080431.

13408080666731 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13408080666731 - 2⁴² = 9010034155627 is a prime.

It is a super-2 number, since 2×13408080666731² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13408080660731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6704040333365 + 6704040333366.

It is an arithmetic number, because the mean of its divisors is an integer number (6704040333366).

Almost surely, 2^{13408080666731} is an apocalyptic number.

13408080666731 is a deficient number, since it is larger than the sum of its proper divisors (1).

13408080666731 is an equidigital number, since it uses as much as digits as its factorization.

13408080666731 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3483648, while the sum is 53.

The spelling of 13408080666731 in words is "thirteen trillion, four hundred eight billion, eighty million, six hundred sixty-six thousand, seven hundred thirty-one".