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1340985735611 is a prime number
BaseRepresentation
bin10011100000111000111…
…110100111100110111011
311202012022121020112202222
4103200320332213212323
5133432314322014421
62504012414114255
7165611606453054
oct23407076474673
94665277215688
101340985735611
11477788540a65
12197a854ab98b
13995ba4612c2
1448c92a2d72b
1524d37221cab
hex13838fa79bb

1340985735611 has 2 divisors, whose sum is σ = 1340985735612. Its totient is φ = 1340985735610.

The previous prime is 1340985735581. The next prime is 1340985735619. The reversal of 1340985735611 is 1165375890431.

It is a strong prime.

It is an emirp because it is prime and its reverse (1165375890431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340985735611 is a prime.

It is a super-2 number, since 2×13409857356112 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1340985735619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670492867805 + 670492867806.

It is an arithmetic number, because the mean of its divisors is an integer number (670492867806).

Almost surely, 21340985735611 is an apocalyptic number.

1340985735611 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340985735611 is an equidigital number, since it uses as much as digits as its factorization.

1340985735611 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2721600, while the sum is 53.

The spelling of 1340985735611 in words is "one trillion, three hundred forty billion, nine hundred eighty-five million, seven hundred thirty-five thousand, six hundred eleven".