Base | Representation |
---|---|
bin | 111110011100011111… |
… | …1011001100011110101 |
3 | 110211010200001102122212 |
4 | 1330320333121203311 |
5 | 4144114113130122 |
6 | 141334343103205 |
7 | 12455061204146 |
oct | 1747077314365 |
9 | 424120042585 |
10 | 134100130037 |
11 | 51965033555 |
12 | 21ba5a41b05 |
13 | c851483c93 |
14 | 66c1c45acd |
15 | 374ccb6ce2 |
hex | 1f38fd98f5 |
134100130037 has 2 divisors, whose sum is σ = 134100130038. Its totient is φ = 134100130036.
The previous prime is 134100130019. The next prime is 134100130067. The reversal of 134100130037 is 730031001431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114324458161 + 19775671876 = 338119^2 + 140626^2 .
It is a cyclic number.
It is not a de Polignac number, because 134100130037 - 28 = 134100129781 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134100129994 and 134100130021.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134100130067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67050065018 + 67050065019.
It is an arithmetic number, because the mean of its divisors is an integer number (67050065019).
Almost surely, 2134100130037 is an apocalyptic number.
It is an amenable number.
134100130037 is a deficient number, since it is larger than the sum of its proper divisors (1).
134100130037 is an equidigital number, since it uses as much as digits as its factorization.
134100130037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 756, while the sum is 23.
Adding to 134100130037 its reverse (730031001431), we get a palindrome (864131131468).
The spelling of 134100130037 in words is "one hundred thirty-four billion, one hundred million, one hundred thirty thousand, thirty-seven".
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