1341006674773 has 2 divisors, whose sum is σ = 1341006674774. Its totient is φ = 1341006674772.

The previous prime is 1341006674681. The next prime is 1341006674783. The reversal of 1341006674773 is 3774766001431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1102840226244 + 238166448529 = 1050162^2 + 488023^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1341006674773 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1341006674783) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670503337386 + 670503337387.

It is an arithmetic number, because the mean of its divisors is an integer number (670503337387).

Almost surely, 2^{1341006674773} is an apocalyptic number.

It is an amenable number.

1341006674773 is a deficient number, since it is larger than the sum of its proper divisors (1).

1341006674773 is an equidigital number, since it uses as much as digits as its factorization.

1341006674773 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1778112, while the sum is 49.

The spelling of 1341006674773 in words is "one trillion, three hundred forty-one billion, six million, six hundred seventy-four thousand, seven hundred seventy-three".