Search a number
-
+
13410127676149 is a prime number
BaseRepresentation
bin1100001100100100100111…
…1001011000001011110101
31202110222212212002011010221
43003021021321120023311
53224202420141114044
644304305544014341
72552564315336131
oct303111171301365
952428785064127
1013410127676149
114300226521086
121606b807613b1
13763753597a29
143450a72a43c1
15183c6525d484
hexc3249e582f5

13410127676149 has 2 divisors, whose sum is σ = 13410127676150. Its totient is φ = 13410127676148.

The previous prime is 13410127676119. The next prime is 13410127676159. The reversal of 13410127676149 is 94167672101431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9596922452100 + 3813205224049 = 3097890^2 + 1952743^2 .

It is a cyclic number.

It is not a de Polignac number, because 13410127676149 - 237 = 13272688722677 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13410127676096 and 13410127676105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13410127676119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705063838074 + 6705063838075.

It is an arithmetic number, because the mean of its divisors is an integer number (6705063838075).

Almost surely, 213410127676149 is an apocalyptic number.

It is an amenable number.

13410127676149 is a deficient number, since it is larger than the sum of its proper divisors (1).

13410127676149 is an equidigital number, since it uses as much as digits as its factorization.

13410127676149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1524096, while the sum is 52.

The spelling of 13410127676149 in words is "thirteen trillion, four hundred ten billion, one hundred twenty-seven million, six hundred seventy-six thousand, one hundred forty-nine".