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134103403153 is a prime number
BaseRepresentation
bin111110011100100101…
…1111000101010010001
3110211010220012201112101
41330321023320222101
54144120432400103
6141334541200401
712455131055566
oct1747113705221
9424126181471
10134103403153
1151966969705
1221ba6b60101
13c85205ba35
1466c245886d
15374d211a1d
hex1f392f8a91

134103403153 has 2 divisors, whose sum is σ = 134103403154. Its totient is φ = 134103403152.

The previous prime is 134103403121. The next prime is 134103403157. The reversal of 134103403153 is 351304301431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68283961344 + 65819441809 = 261312^2 + 256553^2 .

It is an emirp because it is prime and its reverse (351304301431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134103403153 - 25 = 134103403121 is a prime.

It is not a weakly prime, because it can be changed into another prime (134103403157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67051701576 + 67051701577.

It is an arithmetic number, because the mean of its divisors is an integer number (67051701577).

Almost surely, 2134103403153 is an apocalyptic number.

It is an amenable number.

134103403153 is a deficient number, since it is larger than the sum of its proper divisors (1).

134103403153 is an equidigital number, since it uses as much as digits as its factorization.

134103403153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 134103403153 its reverse (351304301431), we get a palindrome (485407704584).

The spelling of 134103403153 in words is "one hundred thirty-four billion, one hundred three million, four hundred three thousand, one hundred fifty-three".