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13410422531113 is a prime number
BaseRepresentation
bin1100001100100101101101…
…1110001010010000101001
31202111000122101220100010011
43003021123132022100221
53224204021131443423
644304355115451521
72552604525506446
oct303113336122051
952430571810104
1013410422531113
114300367a00a73
121607043456ba1
1376379c6b3a1a
143450d44d89cd
15183c810a2b0d
hexc325b78a429

13410422531113 has 2 divisors, whose sum is σ = 13410422531114. Its totient is φ = 13410422531112.

The previous prime is 13410422531081. The next prime is 13410422531153. The reversal of 13410422531113 is 31113522401431.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12018369429504 + 1392053101609 = 3466752^2 + 1179853^2 .

It is an emirp because it is prime and its reverse (31113522401431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13410422531113 - 25 = 13410422531081 is a prime.

It is not a weakly prime, because it can be changed into another prime (13410422531153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705211265556 + 6705211265557.

It is an arithmetic number, because the mean of its divisors is an integer number (6705211265557).

Almost surely, 213410422531113 is an apocalyptic number.

It is an amenable number.

13410422531113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13410422531113 is an equidigital number, since it uses as much as digits as its factorization.

13410422531113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 13410422531113 its reverse (31113522401431), we get a palindrome (44523944932544).

The spelling of 13410422531113 in words is "thirteen trillion, four hundred ten billion, four hundred twenty-two million, five hundred thirty-one thousand, one hundred thirteen".