Base | Representation |
---|---|
bin | 1100001100100101101101… |
… | …1110001010010000101001 |
3 | 1202111000122101220100010011 |
4 | 3003021123132022100221 |
5 | 3224204021131443423 |
6 | 44304355115451521 |
7 | 2552604525506446 |
oct | 303113336122051 |
9 | 52430571810104 |
10 | 13410422531113 |
11 | 4300367a00a73 |
12 | 1607043456ba1 |
13 | 76379c6b3a1a |
14 | 3450d44d89cd |
15 | 183c810a2b0d |
hex | c325b78a429 |
13410422531113 has 2 divisors, whose sum is σ = 13410422531114. Its totient is φ = 13410422531112.
The previous prime is 13410422531081. The next prime is 13410422531153. The reversal of 13410422531113 is 31113522401431.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12018369429504 + 1392053101609 = 3466752^2 + 1179853^2 .
It is an emirp because it is prime and its reverse (31113522401431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13410422531113 - 25 = 13410422531081 is a prime.
It is not a weakly prime, because it can be changed into another prime (13410422531153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705211265556 + 6705211265557.
It is an arithmetic number, because the mean of its divisors is an integer number (6705211265557).
Almost surely, 213410422531113 is an apocalyptic number.
It is an amenable number.
13410422531113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13410422531113 is an equidigital number, since it uses as much as digits as its factorization.
13410422531113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 13410422531113 its reverse (31113522401431), we get a palindrome (44523944932544).
The spelling of 13410422531113 in words is "thirteen trillion, four hundred ten billion, four hundred twenty-two million, five hundred thirty-one thousand, one hundred thirteen".
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