13410553104397 has 2 divisors, whose sum is σ = 13410553104398. Its totient is φ = 13410553104396.

The previous prime is 13410553104359. The next prime is 13410553104419. The reversal of 13410553104397 is 79340135501431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13410456396841 + 96707556 = 3662029^2 + 9834^2 .

It is a cyclic number.

It is not a de Polignac number, because 13410553104397 - 2⁴³ = 4614460082189 is a prime.

It is a super-3 number, since 3×13410553104397³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13410553104307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705276552198 + 6705276552199.

It is an arithmetic number, because the mean of its divisors is an integer number (6705276552199).

Almost surely, 2^{13410553104397} is an apocalyptic number.

It is an amenable number.

13410553104397 is a deficient number, since it is larger than the sum of its proper divisors (1).

13410553104397 is an equidigital number, since it uses as much as digits as its factorization.

13410553104397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 680400, while the sum is 46.

The spelling of 13410553104397 in words is "thirteen trillion, four hundred ten billion, five hundred fifty-three million, one hundred four thousand, three hundred ninety-seven".