Base | Representation |
---|---|
bin | 11110011111100001001011… |
… | …111101000010100001110111 |
3 | 122120211112110121221120112111 |
4 | 132133201023331002201313 |
5 | 120034203304241031042 |
6 | 1153120020333431451 |
7 | 40150635506316664 |
oct | 3637411375024167 |
9 | 576745417846474 |
10 | 134107333142647 |
11 | 3980466742a567 |
12 | 1305aa9663b587 |
13 | 59aa3621c95c7 |
14 | 2518b88438a6b |
15 | 107868d461517 |
hex | 79f84bf42877 |
134107333142647 has 2 divisors, whose sum is σ = 134107333142648. Its totient is φ = 134107333142646.
The previous prime is 134107333142641. The next prime is 134107333142663. The reversal of 134107333142647 is 746241333701431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134107333142647 - 23 = 134107333142639 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 134107333142647.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134107333142641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67053666571323 + 67053666571324.
It is an arithmetic number, because the mean of its divisors is an integer number (67053666571324).
Almost surely, 2134107333142647 is an apocalyptic number.
134107333142647 is a deficient number, since it is larger than the sum of its proper divisors (1).
134107333142647 is an equidigital number, since it uses as much as digits as its factorization.
134107333142647 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3048192, while the sum is 49.
The spelling of 134107333142647 in words is "one hundred thirty-four trillion, one hundred seven billion, three hundred thirty-three million, one hundred forty-two thousand, six hundred forty-seven".
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