Base | Representation |
---|---|
bin | 10011100000111111110… |
… | …100000010010101100110 |
3 | 11202012121121000012112002 |
4 | 103200333310002111212 |
5 | 133433033200331042 |
6 | 2504032031525302 |
7 | 165614501221343 |
oct | 23407764022546 |
9 | 4665547005462 |
10 | 1341100402022 |
11 | 47783723a597 |
12 | 197ab7989832 |
13 | 9960813b654 |
14 | 48ca3d5b7ca |
15 | 24d42322132 |
hex | 1383fd02566 |
1341100402022 has 8 divisors (see below), whose sum is σ = 2011655523672. Its totient is φ = 670548560800.
The previous prime is 1341100401919. The next prime is 1341100402067. The reversal of 1341100402022 is 2202040011431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 1341100401985 and 1341100402003.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1117697 + ... + 1982787.
It is an arithmetic number, because the mean of its divisors is an integer number (251456940459).
Almost surely, 21341100402022 is an apocalyptic number.
1341100402022 is a deficient number, since it is larger than the sum of its proper divisors (670555121650).
1341100402022 is an equidigital number, since it uses as much as digits as its factorization.
1341100402022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1640214.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1341100402022 its reverse (2202040011431), we get a palindrome (3543140413453).
The spelling of 1341100402022 in words is "one trillion, three hundred forty-one billion, one hundred million, four hundred two thousand, twenty-two".
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