Base | Representation |
---|---|
bin | 10011100000111111110… |
… | …100000010010011111111 |
3 | 11202012121121000012101021 |
4 | 103200333310002103333 |
5 | 133433033200330134 |
6 | 2504032031525011 |
7 | 165614501221135 |
oct | 23407764022377 |
9 | 4665547005337 |
10 | 1341100401919 |
11 | 47783723a503 |
12 | 197ab7989767 |
13 | 9960813b5a5 |
14 | 48ca3d5b755 |
15 | 24d423220b4 |
hex | 1383fd024ff |
1341100401919 has 2 divisors, whose sum is σ = 1341100401920. Its totient is φ = 1341100401918.
The previous prime is 1341100401917. The next prime is 1341100402067. The reversal of 1341100401919 is 9191040011431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1341100401919 - 21 = 1341100401917 is a prime.
It is a super-2 number, since 2×13411004019192 (a number of 25 digits) contains 22 as substring.
Together with 1341100401917, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1341100401913) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670550200959 + 670550200960.
It is an arithmetic number, because the mean of its divisors is an integer number (670550200960).
Almost surely, 21341100401919 is an apocalyptic number.
1341100401919 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341100401919 is an equidigital number, since it uses as much as digits as its factorization.
1341100401919 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 34.
The spelling of 1341100401919 in words is "one trillion, three hundred forty-one billion, one hundred million, four hundred one thousand, nine hundred nineteen".
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