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134110111452000 = 25353103911075531
BaseRepresentation
bin11110011111100011110001…
…100011011100101101100000
3122120211210122020211022110220
4132133203301203130231200
5120034230002012431000
61153121200142323040
740151064403465155
oct3637436143345540
9576753566738426
10134110111452000
11398058627424a2
121305b530b89480
1359aa6b59a0a38
142518d6d41422c
1510787a23141a0
hex79f8f18dcb60

134110111452000 has 192 divisors, whose sum is σ = 439387414921728. Its totient is φ = 35759221440000.

The previous prime is 134110111451983. The next prime is 134110111452001. The reversal of 134110111452000 is 254111011431.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134110111452001) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 124154235 + ... + 125229765.

It is an arithmetic number, because the mean of its divisors is an integer number (2288476119384).

Almost surely, 2134110111452000 is an apocalyptic number.

134110111452000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134110111452000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (219693707460864).

134110111452000 is an abundant number, since it is smaller than the sum of its proper divisors (305277303469728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134110111452000 is a wasteful number, since it uses less digits than its factorization.

134110111452000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1085950 (or 1085932 counting only the distinct ones).

The product of its (nonzero) digits is 480, while the sum is 24.

Adding to 134110111452000 its reverse (254111011431), we get a palindrome (134364222463431).

The spelling of 134110111452000 in words is "one hundred thirty-four trillion, one hundred ten billion, one hundred eleven million, four hundred fifty-two thousand".