Base | Representation |
---|---|
bin | 1100001100101001000000… |
… | …0010010001011110101111 |
3 | 1202111002220212022120210002 |
4 | 3003022100002101132233 |
5 | 3224212322412204403 |
6 | 44305022421334515 |
7 | 2552635424415122 |
oct | 303122002213657 |
9 | 52432825276702 |
10 | 13411304413103 |
11 | 430077a788a63 |
12 | 160724a86743b |
13 | 7638b030579c |
14 | 34517969a3b9 |
15 | 183cd3701188 |
hex | c32900917af |
13411304413103 has 2 divisors, whose sum is σ = 13411304413104. Its totient is φ = 13411304413102.
The previous prime is 13411304413069. The next prime is 13411304413141. The reversal of 13411304413103 is 30131440311431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13411304413103 - 232 = 13407009445807 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411304413153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705652206551 + 6705652206552.
It is an arithmetic number, because the mean of its divisors is an integer number (6705652206552).
Almost surely, 213411304413103 is an apocalyptic number.
13411304413103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411304413103 is an equidigital number, since it uses as much as digits as its factorization.
13411304413103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 13411304413103 its reverse (30131440311431), we get a palindrome (43542744724534).
The spelling of 13411304413103 in words is "thirteen trillion, four hundred eleven billion, three hundred four million, four hundred thirteen thousand, one hundred three".
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