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1341140302303 = 4728534900049
BaseRepresentation
bin10011100001000010001…
…100001111100111011111
311202012201101002100102021
4103201002030033213133
5133433123404133203
62504040015041011
7165615464322604
oct23410214174737
94665641070367
101341140302303
1147785781222a
12197b09210167
139961349b999
1448ca93866ab
1524d45aa45bd
hex1384230f9df

1341140302303 has 4 divisors (see below), whose sum is σ = 1369675202400. Its totient is φ = 1312605402208.

The previous prime is 1341140302291. The next prime is 1341140302373. The reversal of 1341140302303 is 3032030411431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1341140302303 - 221 = 1341138205151 is a prime.

It is a super-2 number, since 2×13411403023032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341140302373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14267449978 + ... + 14267450071.

It is an arithmetic number, because the mean of its divisors is an integer number (342418800600).

Almost surely, 21341140302303 is an apocalyptic number.

1341140302303 is a deficient number, since it is larger than the sum of its proper divisors (28534900097).

1341140302303 is an equidigital number, since it uses as much as digits as its factorization.

1341140302303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28534900096.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1341140302303 its reverse (3032030411431), we get a palindrome (4373170713734).

The spelling of 1341140302303 in words is "one trillion, three hundred forty-one billion, one hundred forty million, three hundred two thousand, three hundred three".

Divisors: 1 47 28534900049 1341140302303