Base | Representation |
---|---|
bin | 10011100001000010001… |
… | …100010010001110110011 |
3 | 11202012201101002220002212 |
4 | 103201002030102032303 |
5 | 133433123410004021 |
6 | 2504040015202335 |
7 | 165615464366042 |
oct | 23410214221663 |
9 | 4665641086085 |
10 | 1341140313011 |
11 | 47785781a284 |
12 | 197b092163ab |
13 | 996134a3815 |
14 | 48ca938a559 |
15 | 24d45aa785b |
hex | 138423123b3 |
1341140313011 has 2 divisors, whose sum is σ = 1341140313012. Its totient is φ = 1341140313010.
The previous prime is 1341140312927. The next prime is 1341140313017. The reversal of 1341140313011 is 1103130411431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1341140313011 - 214 = 1341140296627 is a prime.
It is a super-2 number, since 2×13411403130112 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1341140313017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670570156505 + 670570156506.
It is an arithmetic number, because the mean of its divisors is an integer number (670570156506).
Almost surely, 21341140313011 is an apocalyptic number.
1341140313011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341140313011 is an equidigital number, since it uses as much as digits as its factorization.
1341140313011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 1341140313011 its reverse (1103130411431), we get a palindrome (2444270724442).
The spelling of 1341140313011 in words is "one trillion, three hundred forty-one billion, one hundred forty million, three hundred thirteen thousand, eleven".
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